$(a)$ The peak voltage of an $ac$ supply is $300 \; V$. What is the $rms$ voltage?
$(b)$ The $rms$ value of current in an $ac$ circuit is $10 \; A$. What is the peak current?
$(b)$ The $rms$ value of current in an $ac$ circuit is $10 \; A$. What is the peak current?
(N/A) Given,peak voltage $V_{0} = 300 \; V$.
The $rms$ voltage is given by the relation $V_{rms} = \frac{V_{0}}{\sqrt{2}}$.
Substituting the values: $V_{rms} = \frac{300}{1.414} \approx 212.1 \; V$.
$(b)$ Given,$rms$ current $I_{rms} = 10 \; A$.
The peak current $I_{0}$ is given by the relation $I_{0} = \sqrt{2} \times I_{rms}$.
Substituting the values: $I_{0} = 1.414 \times 10 = 14.14 \; A$.
The $rms$ voltage is given by the relation $V_{rms} = \frac{V_{0}}{\sqrt{2}}$.
Substituting the values: $V_{rms} = \frac{300}{1.414} \approx 212.1 \; V$.
$(b)$ Given,$rms$ current $I_{rms} = 10 \; A$.
The peak current $I_{0}$ is given by the relation $I_{0} = \sqrt{2} \times I_{rms}$.
Substituting the values: $I_{0} = 1.414 \times 10 = 14.14 \; A$.
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