$A$ and $B$ throw a die alternatively till one of them gets a '$6$' and wins the game. Find their respective probabilities of winning,if $A$ starts first.

  • A
    $P(A) = \frac{6}{11}, P(B) = \frac{5}{11}$
  • B
    $P(A) = \frac{5}{11}, P(B) = \frac{6}{11}$
  • C
    $P(A) = \frac{1}{2}, P(B) = \frac{1}{2}$
  • D
    $P(A) = \frac{36}{91}, P(B) = \frac{25}{91}$

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