$A$ and $B$ are two events such that $P(A)=0.54$,$P(B)=0.69$ and $P(A \cap B)=0.35$. Find $P(A \cup B)$.
- A$0.88$
- B$0.78$
- C$0.98$
- D$0.68$
Explore More
Similar Questions
If $A$ and $B$ are two independent events,then the probability of occurrence of at least one of $A$ and $B$ is given by $1 - P(A') P(B')$. Is this statement true or false?
Medium
View Solution$A$ card is drawn from a pack of $52$ cards. $A$ gambler bets that it is a spade or an ace. What are the odds against his winning this bet?
Easy
View SolutionIf the probability of an event occurring is $3:8$,what is the probability of the event not occurring?
Easy
View SolutionFill in the blanks in the following table:
$P(A)$ $P(B)$ $P(A \cap B)$ $P(A \cup B)$ $\frac{1}{3}$ $\frac{1}{5}$ $\frac{1}{15}$ $........$
| $P(A)$ | $P(B)$ | $P(A \cap B)$ | $P(A \cup B)$ |
| $\frac{1}{3}$ | $\frac{1}{5}$ | $\frac{1}{15}$ | $........$ |
Easy
View SolutionIf one card is drawn at random from a pack of $52$ cards,what is the probability that it is a king or a spade?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo