$p-$Dichlorobenzene has a higher $m.p.$ than those of $o-$ and $m-$ isomers. Discuss.

The chemicals used for preparing acetophenone via Friedel-Crafts acylation are:
$(A)$ $C_6H_6$
$(B)$ $CH_3COCH_3$
$(C)$ $CH_3COCl$
$(D)$ Anhydrous $AlCl_3$

Two statements are given below:
Statement $I$: Chlorobenzene on nitration gives $1-$chloro$-4-$nitrobenzene as the major product.
Statement $II$: Chlorobenzene undergoes nitration more slowly than benzene.
Identify the correct answer.

Chlorobenzene on fusing with solid $NaOH$ gives

The compounds $P$,$Q$,and $S$ were separately subjected to nitration using $HNO_3 / H_2SO_4$ mixture. The major product formed in each case respectively,is

The reaction of compound $P$ with $CH_3MgBr$ (excess) in $(C_2H_5)_2O$ followed by addition of $H_2O$ gives $Q$. The compound $Q$ on treatment with $H_2SO_4$ at $0^{\circ}C$ gives $R$. The reaction of $R$ with $CH_3COCl$ in the presence of anhydrous $AlCl_3$ in $CH_2Cl_2$ followed by treatment with $H_2O$ produces compound $S$ [$Et$ in compound $P$ is ethyl group].
$(1)$ The product $S$ is
$(2)$ The reactions,$Q$ to $R$ and $R$ to $S$,are

$A$. Dehydration and Friedel-Crafts acylation	$B$. Aromatic sulfonation and Friedel-Crafts acylation
$C$. Friedel-Crafts alkylation,dehydration and Friedel-Crafts acylation	$D$. Friedel-Crafts alkylation and Friedel-Crafts acylation

Given the answer question $(1)$ and $(2)$