Evaluate sqrt{6.5 - 6.32} considering the rul | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) First,perform the subtraction inside the square root: $6.5 - 6.32 = 0.18$.According to the rules of significant figures for subtraction,the result

Vedclass · Accepted Answer

$0.42$

Vedclass · Answer

(B) First,perform the subtraction inside the square root: $6.5 - 6.32 = 0.18$.According to the rules of significant figures for subtraction,the result should have the same number of decimal places as the measurement with the fewest decimal places. Here,$6.5$ has one decimal place,so the result $0.18$ should be rounded to one decimal place,which is $0.2$.However,if we perform the calculation as $\sqrt{0.18} \approx 0.42426...$,we must apply the rules of significant figures to the final result.The number $0.18$ has two significant figures. Therefore,the final result should be rounded to two significant figures.Rounding $0.42426...$ to two significant figures gives $0.42$.

Evaluate $\sqrt{6.5 - 6.32}$ considering the rules of significant figures.

Similar Questions

Statement-$1$: All reliable digits plus the first uncertain digit together are called significant figures.
Statement-$2$: Trailing zero$(s)$ in a number with a decimal point are never significant.

The diameter of a wire is measured to be $0.0205 \times 10^{-4} \,m$. The number of significant figures in the measurement is

The radius of a thin wire is $0.16 \; mm$. The area of cross-section taking significant figures into consideration in square millimeters is?

The decimal equivalent of $\frac{1}{20}$ up to three significant figures is

The area of a sheet of length $10.2 \,cm$ and width $6.8 \,cm$ expressed up to the proper number of significant figures is ......... $cm^2$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module