Can titrations with $KMnO_4$ be performed in the presence of $HCl$? Why?
(A) No,titrations with $KMnO_4$ cannot be performed in the presence of $HCl$.
$HCl$ is a reducing agent and it reacts with $KMnO_4$ to produce $Cl_2$ gas.
The reaction is: $2KMnO_4 + 16HCl \rightarrow 2KCl + 2MnCl_2 + 8H_2O + 5Cl_2$.
This reaction interferes with the titration process by consuming the titrant and producing a gas,leading to inaccurate results.
$HCl$ is a reducing agent and it reacts with $KMnO_4$ to produce $Cl_2$ gas.
The reaction is: $2KMnO_4 + 16HCl \rightarrow 2KCl + 2MnCl_2 + 8H_2O + 5Cl_2$.
This reaction interferes with the titration process by consuming the titrant and producing a gas,leading to inaccurate results.
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