Match the numbers in Column-I with the number | vedclass

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(A) To determine the number of significant figures,we follow these rules:$1$. For $2.85 	imes 10^{26} \ kg$: The power of $10$ does not contribute to

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$(1)-(c), (2)-(a), (3)-(b)$

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(A) To determine the number of significant figures,we follow these rules:$1$. For $2.85 	imes 10^{26} \ kg$: The power of $10$ does not contribute to significant figures. The digits $2, 8, 5$ are all non-zero,so there are $3$ significant figures. Thus,$(1)-(c)$.$2$. For $0.009 \ m^2$: Leading zeros are not significant. Only the digit $9$ is significant. Thus,there is $1$ significant figure. Thus,$(2)-(a)$.$3$. For $0.060 \ s$: Leading zeros are not significant. The trailing zero after a decimal point is significant. Thus,the digits $6$ and $0$ are significant,giving $2$ significant figures. Thus,$(3)-(b)$.Therefore,the correct matching is $(1)-(c), (2)-(a), (3)-(b)$.

Column-$I$	Column-$II$
$(1)$ $2.85 \times 10^{26} \ kg$	$(a)$ $1$
$(2)$ $0.009 \ m^2$	$(b)$ $2$
$(3)$ $0.060 \ s$	$(c)$ $3$

Match the numbers in Column-$I$ with the number of significant figures in Column-$II$.

Column-$I$ Column-$II$

$(1)$ $2.85 \times 10^{26} \ kg$ $(a)$ $1$

$(2)$ $0.009 \ m^2$ $(b)$ $2$

$(3)$ $0.060 \ s$ $(c)$ $3$

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Match the numbers in Column-$I$ with the number of significant figures in Column-$II$. Column-$I$ Column-$II$ $(1)$ $2.85 \times 10^{26} \ kg$ $(a)$ $1$ $(2)$ $0.009 \ m^2$ $(b)$ $2$ $(3)$ $0.060 \ s$ $(c)$ $3$