Perform the subtraction considering significa | vedclass

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(B) To subtract numbers in scientific notation,we first express them with the same power of $10$.$3.9 	imes 10^5 = 39.0 	imes 10^4$.Now,perform the

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$3.6 	imes 10^5$

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(B) To subtract numbers in scientific notation,we first express them with the same power of $10$.$3.9 	imes 10^5 = 39.0 	imes 10^4$.Now,perform the subtraction: $(39.0 	imes 10^4) - (2.5 	imes 10^4) = (39.0 - 2.5) 	imes 10^4 = 36.5 	imes 10^4$.Convert this back to standard scientific notation: $3.65 	imes 10^5$.According to the rules of significant figures for subtraction,the result should be reported to the same number of decimal places as the measurement with the fewest decimal places. Here,$3.9 	imes 10^5$ has one decimal place (when expressed as $39.0 	imes 10^4$) and $2.5 	imes 10^4$ has one decimal place. Thus,the result should be rounded to one decimal place.Rounding $3.65 	imes 10^5$ to one decimal place gives $3.6 	imes 10^5$ (following the rule of rounding to the nearest even number or standard rounding convention).

List-$I$ (Number)	List-$II$ (Significant figures)
$A. 1001$	$I. 3$
$B. 010.1$	$II. 4$
$C. 100.100$	$III. 5$
$D. 0.0010010$	$IV. 6$

Perform the subtraction considering significant figures: $3.9 \times 10^5 - 2.5 \times 10^4$

Similar Questions

Match List-$I$ with List-$II$.

List-$I$ (Number) List-$II$ (Significant figures)

$A. 1001$ $I. 3$

$B. 010.1$ $II. 4$

$C. 100.100$ $III. 5$

$D. 0.0010010$ $IV. 6$

Choose the correct answer from the options given below:

Evaluate $\sqrt{6.5 - 6.32}$ considering the rules of significant figures.

If the value of resistance is $10.845 \, \Omega$ and the value of current is $3.23 \, \text{A}$,the value of potential with significant figures would be ........... $V$.

$5.74 \; g$ of a substance occupies $1.2 \; cm^3$. Express its density (in $g/cm^3$) by keeping the significant figures in view.

Round off the value $2.845$ to three significant figures.

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