Match Column-$I$ with Column-$II$.
Column-$I$ Column-$II$ $(1)$ Vertical component of velocity is zero $(a)$ Tangent to the parabolic path $(2)$ Linear velocity $(b)$ Maximum height point of the projectile trajectory
| Column-$I$ | Column-$II$ |
|---|---|
| $(1)$ Vertical component of velocity is zero | $(a)$ Tangent to the parabolic path |
| $(2)$ Linear velocity | $(b)$ Maximum height point of the projectile trajectory |
(A) At the maximum height of a projectile's trajectory,the vertical component of velocity $(v_y)$ becomes zero. Thus,$(1)$ matches with $(b)$.
The linear velocity vector at any point on the trajectory is always directed tangent to the parabolic path. Thus,$(2)$ matches with $(a)$.
Therefore,the correct matching is $(1-b, 2-a)$.
The linear velocity vector at any point on the trajectory is always directed tangent to the parabolic path. Thus,$(2)$ matches with $(a)$.
Therefore,the correct matching is $(1-b, 2-a)$.
Explore More
Similar Questions
$A$ cricket player can throw a ball with an initial speed of $30 \,m/s$. What is the maximum range the player can throw the ball? Neglect air resistance. [Take $g = 10 \,m/s^2$]
$A$ body is projected from the ground at an angle of $\tan^{-1}(\frac{8}{7})$ with the horizontal. The ratio of the maximum height attained by it to its range is (in $: 7$)
$A$ bomb of mass $m$ is projected from the ground with speed $v$ at an angle $\theta$ with the horizontal. At the maximum height from the ground,it explodes into two fragments of equal mass. If one fragment comes to rest immediately after the explosion,then the horizontal range of the centre of mass is ..............
Easy
View Solution$A$ body is projected horizontally from a tower with a velocity of $18 \, ms^{-1}$. It strikes the ground at an angle of $45^o$. The vertical component of the velocity when it strikes the ground is ........ $ms^{-1}$.
Medium
View Solution$A$ body is projected at $t = 0$ with a velocity $10\,ms^{-1}$ at an angle of $60^\circ$ with the horizontal. The radius of curvature of its trajectory at $t = 1\,s$ is $R$. Neglecting air resistance and taking acceleration due to gravity $g = 10\,ms^{-2}$,the value of $R$ is ........ $m$.
DifficultJEE MAIN 2019
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo