What is the ratio of the angular speed of the | vedclass

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Question

(A) The angular speed $\omega$ is given by $\omega = \frac{2\pi}{T}$,where $T$ is the time period.For the hour hand,the time period $T_h = 12 	ext{ h

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$1: 12$

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(A) The angular speed $\omega$ is given by $\omega = \frac{2\pi}{T}$,where $T$ is the time period.For the hour hand,the time period $T_h = 12 	ext{ hours} = 12 	imes 3600 	ext{ s}$.So,$\omega_h = \frac{2\pi}{12 	imes 3600} 	ext{ rad/s}$.For the minute hand,the time period $T_m = 1 	ext{ hour} = 3600 	ext{ s}$.So,$\omega_m = \frac{2\pi}{3600} 	ext{ rad/s}$.The ratio of the angular speed of the hour hand to the minute hand is:$\frac{\omega_h}{\omega_m} = \frac{2\pi / (12 	imes 3600)}{2\pi / 3600} = \frac{3600}{12 	imes 3600} = \frac{1}{12}$.Thus,the ratio is $1: 12$.

What is the ratio of the angular speed of the hour hand to the minute hand of a clock?

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