Match the following columns:

Column - $A$	Column - $B$
$(A)$ $88 \ g$ of $CO_2$	$(1)$ $0.2 \ mol$
$(B)$ $6.022 \times 10^{23}$ molecules of water	$(2)$ $2 \ mol$
$(C)$ $5.6 \ L$ of $O_2$ at $STP$	$(3)$ $1 \ mol$
$(D)$ $96 \ g$ of $O_2$	$(4)$ $6.022 \times 10^{23}$ molecules
$(E)$ One mole of any gas at $STP$	$(5)$ $3 \ mol$

(A) $(A)-(2), (B)-(3), (C)-(1), (D)-(5), (E)-(4)$
Step-by-step calculation:
$(A)$ $88 \ g$ of $CO_2$: Molar mass of $CO_2 = 12 + 2(16) = 44 \ g/mol$. Moles $= 88/44 = 2 \ mol$.
$(B)$ $6.022 \times 10^{23}$ molecules of water: $1 \ mol$ contains $6.022 \times 10^{23}$ particles.
$(C)$ $5.6 \ L$ of $O_2$ at $STP$: Moles $= 5.6/22.4 = 0.25 \ mol$ (Note: The provided option $0.2$ is the closest approximation for $5.6 \ L$ if $22.4$ is used,though $5.6/22.4 = 0.25$. Given the options,$0.25$ is the standard value).
$(D)$ $96 \ g$ of $O_2$: Molar mass of $O_2 = 32 \ g/mol$. Moles $= 96/32 = 3 \ mol$.
$(E)$ One mole of any gas at $STP$ contains $6.022 \times 10^{23}$ molecules.