State the de Broglie principle.
- AMatter exhibits dual behavior: particle-like and wave-like.
- BEnergy is emitted in discrete packets called quanta.
- CIt is impossible to determine the exact position and momentum of an electron simultaneously.
- DElectrons occupy orbitals in increasing order of energy.
Explore More
Similar Questions
The mass of an electron is $9.1 \times 10^{-31} \ kg$. If its $K.E.$ is $3.0 \times 10^{-25} \ J$,calculate its wavelength.
Medium
View SolutionWhat will be the de Broglie wavelength associated with a charged proton in $\mathring{A}$? ($V =$ potential difference)
Difficult
View SolutionThe basis of the quantum mechanical model of an atom is:
If the radius of the first orbit of hydrogen atom is $a_0$, then de Broglie's wavelength of electron in $3^{rd}$ orbit is (in $\pi a_0$)
If $a_0$ is the Bohr radius,then the de-Broglie wavelength of an electron revolving in the second excited state of the $H$ atom will be:
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo