Which bond is shorter: $C=O$ or $N=O$? Why?

In the $Al_2Cl_6$ dimer,which of the following statements is true regarding the $Al-Cl$ bonds?

Which of the following statement$(s)$ is/are correct? [$T$ for True and $F$ for False$]$
$(a)$ Hybrid orbitals form stronger bonds than pure atomic orbitals.
$(b)$ Canonical structures have a difference in the arrangement of atoms $w.r.t.$ each other.
$(c)$ Any symmetrical molecule always contains the same bond angle.
$(d)$ $VSEPR$ theory can explain the square planar geometry of $XeF_4$.

Match the following species in List-$I$ with the number of lone pairs in List-$II$.

List-$I$ (Species)	List-$II$ (Number of lone pairs)
$A. \ CH_3COCH_3$	$I. \ 2$
$B. \ CH_3CO^+$	$II. \ 0$
$C. \ CH_3CH_2^+$	$III. \ 1$
	$IV. \ 3$

Which of the following molecules does not form in the $I^{st}$ excited state of the central atom?

Match the species in List-$I$ with their geometry in List-$II$:

List-$I$	List-$II$
$A. PCl_5$	$I. \text{Tetrahedral}$
$B. BrF_5$	$II. \text{Square Planar}$
$C. BF_4^-$	$III. \text{Trigonal bipyramidal}$
$D. [Ni(CN)_4]^{2-}$	$IV. \text{Square pyramidal}$

Choose the correct answer from the options given below: