Why is the bond angle in $CH_4$ not $90^{\circ}$,even though the outermost $p$-orbitals of carbon are at $90^{\circ}$ to each other?
- ADue to $sp$ hybridization
- BDue to $sp^2$ hybridization
- CDue to $sp^3$ hybridization
- DDue to $dsp^2$ hybridization
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Similar Questions
Structure of $IF_4^+$ and hybridization of iodine in this structure are
Medium
View SolutionMatch the following ions with the corresponding hybridisation of their central atoms.
$A. NO_3^-$ $1. sp^3$ $B. NH_2^-$ $2. sp$ $C. SCN^-$ $3. sp^3d$ $D. ICl_2^-$ $4. sp^2$
| $A. NO_3^-$ | $1. sp^3$ |
| $B. NH_2^-$ | $2. sp$ |
| $C. SCN^-$ | $3. sp^3d$ |
| $D. ICl_2^-$ | $4. sp^2$ |
What is the hybridization of carbon in graphite and diamond,respectively?
Easy
View SolutionFill in the blanks:
$(i)$ Based on the type of overlapping,covalent bonds are classified into ........ and .......... .
$(ii)$ The bond formation involving hybrid orbitals is called ............. .
$(iii)$ The type of hybridization observed in the $C_2H_6$ molecule is ........... .
$(iv)$ The type of hybridization observed in the $BrF_5$ complex is ............... .
$(i)$ Based on the type of overlapping,covalent bonds are classified into ........ and .......... .
$(ii)$ The bond formation involving hybrid orbitals is called ............. .
$(iii)$ The type of hybridization observed in the $C_2H_6$ molecule is ........... .
$(iv)$ The type of hybridization observed in the $BrF_5$ complex is ............... .
Medium
View SolutionThe molecule of $CO_2$ has a $180^{\circ}$ bond angle. It can be explained on the basis of:
Medium
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