The molecule of $CO_2$ has a $180^{\circ}$ bond angle. It can be explained on the basis of:

  • A
    $sp^3$ hybridisation
  • B
    $sp^2$ hybridisation
  • C
    $sp$ hybridisation
  • D
    $d^2sp^3$ hybridisation

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$(II) CH \equiv C - C \equiv CH$
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$(IV) CH_2 = CH - CH = CH_2$

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One of the following conversions results in the change of hybridization and geometry:

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