One of the following conversions results in t | vedclass

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(C) For the conversion $CH_4 \rightarrow C_2H_6$,there is no change in the hybridization of the carbon atom. Both $CH_4$ and $C_2H_6$ have $sp^3$ hybr

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$BF_3$ to $BF_4^-$

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(C) For the conversion $CH_4 \rightarrow C_2H_6$,there is no change in the hybridization of the carbon atom. Both $CH_4$ and $C_2H_6$ have $sp^3$ hybridization and tetrahedral geometry.For the conversion $NH_3 \rightarrow NH_4^+$,nitrogen in $NH_3$ is $sp^3$ hybridized with a pyramidal shape. In $NH_4^+$,it remains $sp^3$ hybridized but the geometry becomes tetrahedral.For the conversion $H_2O \rightarrow H_3O^+$,oxygen in $H_2O$ is $sp^3$ hybridized with a bent shape. In $H_3O^+$,it remains $sp^3$ hybridized but the shape becomes pyramidal.For the conversion $BF_3 \rightarrow BF_4^-$,boron in $BF_3$ is $sp^2$ hybridized with a trigonal planar geometry. In $BF_4^-$,the hybridization changes to $sp^3$ and the geometry changes to tetrahedral.

Column $I$ (Molecule/ion)	Column $II$ (Hybridisation)
$A$. $H_3O^{+}$	$P$. $sp$
$B$. $NH_2^{-}$	$Q$. $sp^2$
$C$. $NO_3^{-}$	$R$. $sp^3$
$D$. $ClF_3$	$S$. $sp^3d$

One of the following conversions results in the change of hybridization and geometry:

Similar Questions

What is the type of hybridization of $N$ in $NH_3$?

In $HCHO$,the carbon atom has which hybridization?

Identify the correct match:

Column $I$ (Molecule/ion) Column $II$ (Hybridisation)

$A$. $H_3O^{+}$ $P$. $sp$

$B$. $NH_2^{-}$ $Q$. $sp^2$

$C$. $NO_3^{-}$ $R$. $sp^3$

$D$. $ClF_3$ $S$. $sp^3d$

In allene $(C_3H_4)$,the type of hybridization of the carbon atoms is (are)

In $Cl_2O_{6(l)} + HF \to P + Q$. If $H$ of acid $HF$ attaches with $Q$,then identify the correct option for hybridization of $Cl$ atom and $\angle OClO$ in the $P$ and $Q$ ions.

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