What is the type of hybridization of N in NH_ | vedclass

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(B) The total number of valence electrons in $NH_3$ is $5 + (3 	imes 1) = 8$. Using the formula for steric number $X = \frac{1}{2} (V + M - C + A)$,w

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$sp^3$

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(B) The total number of valence electrons in $NH_3$ is $5 + (3 	imes 1) = 8$. Using the formula for steric number $X = \frac{1}{2} (V + M - C + A)$,where $V = 5$ (valence electrons of $N$),$M = 3$ (monovalent atoms),$C = 0$,and $A = 0$. $X = \frac{8}{2} = 4$. Since the steric number is $4$,the hybridization is $sp^3$.

What is the type of hybridization of $N$ in $NH_3$?

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