What can be concluded from the order of boiling points of ether,carbon tetrachloride,ethanol,and water?
(N/A) The boiling point is directly related to the strength of intermolecular forces of attraction. Higher boiling points indicate stronger intermolecular forces. Therefore,it can be concluded that the intermolecular forces of attraction increase in the order: $\text{Ether} < \text{Carbon tetrachloride} < \text{Ethanol} < \text{Water}$.
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Similar Questions
The correct order of boiling points of the compounds given below is-
$A$) Methoxy ethane
$B$) Propan-$1$-ol
$C$) Propanal
$D$) Propanone
$A$) Methoxy ethane
$B$) Propan-$1$-ol
$C$) Propanal
$D$) Propanone
Identify product $B$ in the following reaction sequence:
$(CH_3)_2C=C(CH_3)_2$ $\xrightarrow{X_2, H_2O} A$ $\xrightarrow{OH^{-}} B$
$(CH_3)_2C=C(CH_3)_2$ $\xrightarrow{X_2, H_2O} A$ $\xrightarrow{OH^{-}} B$
Select the correct statement.
Medium
View SolutionIdentify the incorrect match with respect to compounds to be distinguished and the reagent used.
Match the structures in Column-$I$ with their common names in Column-$II$ and $\text{IUPAC}$ names in Column-$III$.
Column-$I$ Column-$II$ (Common Name) Column-$III$ ($\text{IUPAC}$ Name) $(A)$ Phenol $(1)$ Resorcinol $(i)$ Benzene$-1,2-$diol $(B)$ Benzene$-1,3-$diol $(2)$ Catechol (ii) Phenol $(C)$ Benzene$-1,2-$diol $(3)$ Phenol (iii) Benzene$-1,4-$diol $(D)$ Benzene$-1,4-$diol $(4)$ Hydroquinone (iv) Benzene$-1,3-$diol
| Column-$I$ | Column-$II$ (Common Name) | Column-$III$ ($\text{IUPAC}$ Name) |
|---|---|---|
| $(A)$ Phenol | $(1)$ Resorcinol | $(i)$ Benzene$-1,2-$diol |
| $(B)$ Benzene$-1,3-$diol | $(2)$ Catechol | (ii) Phenol |
| $(C)$ Benzene$-1,2-$diol | $(3)$ Phenol | (iii) Benzene$-1,4-$diol |
| $(D)$ Benzene$-1,4-$diol | $(4)$ Hydroquinone | (iv) Benzene$-1,3-$diol |
Medium
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