Select the correct statement.

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(D) Option $(A)$ is correct because the carbocation formed from $(CH_3)_2C=CH-CH_2-Cl$ is resonance-stabilized,making it much more reactive in solvoly

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All of these

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(D) Option $(A)$ is correct because the carbocation formed from $(CH_3)_2C=CH-CH_2-Cl$ is resonance-stabilized,making it much more reactive in solvolysis compared to a simple alkyl chloride.Option $(B)$ is correct because the reaction of $CH_3-CH=CH-CH_2-OH$ with $HBr$ involves the formation of an allylic carbocation intermediate,which can be attacked by $Br^-$ at two different positions,leading to a mixture of $1$-bromo-$2$-butene and $3$-bromo-$1$-butene.Option $(C)$ is correct because $3$-buten-$2$-ol in aqueous acid undergoes protonation and loss of water to form an allylic carbocation,which can be attacked by water at either the $C-1$ or $C-3$ position,leading to an equilibrium mixture of $3$-buten-$2$-ol and $2$-buten-$1$-ol.Since all statements are correct,the correct answer is $(D)$.

List-$I$	List-$II$
$A$. Phenol $\rightarrow$ Salicylaldehyde	$I$. $Br_2$ in $CS_2$
$B$. Phenol $\rightarrow$ Benzene	$II$. $Na_2Cr_2O_7/H_2SO_4$
$C$. Phenol $\rightarrow$ $p$-Benzoquinone	$III$. $Zn$
$D$. Phenol $\rightarrow$ $p$-Bromophenol	$IV$. $CHCl_3/NaOH$

Column-$I$ (Reaction)	Column-$II$ (Product and Reaction Name)
$A$. Phenol $+$ dilute $HNO_3$	$i$. Mononitrophenol,Nitration
$B$. Phenol $+$ Bromine water	$ii$. $2,4,6$-Tribromophenol,Bromination
$C$. Phenol $+$ $Na_2Cr_2O_7/H_2SO_4$	$iii$. Benzoquinone,Oxidation
$D$. Sodium phenoxide $+$ $CO_2$ followed by $H^+$	$iv$. Salicylic acid,Kolbe reaction

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The major product in the following reaction sequence is:

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Which response contains all the correct statements about this process?
$1.$ Dehydration
$2.$ $E_2$ mechanism
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$4.$ Most stable alkene will form
$5.$ Single-step reaction

Diols $(I-IV)$ which react with $CrO_3$ in aqueous $H_2SO_4$ and yield products that readily undergo decarboxylation on heating,are

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