0.24 g of an organic compound gave 0.22 g C | vedclass

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(A) Step $1$: Calculate the percentage of Carbon $(C)$:$\% 	ext{ of } C = \frac{12}{44} 	imes \frac{	ext{Mass of } CO_2}{	ext{Mass of compound}} \

Vedclass · Accepted Answer

$25$ and $73.34$

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(A) Step $1$: Calculate the percentage of Carbon $(C)$:$\% 	ext{ of } C = \frac{12}{44} 	imes \frac{	ext{Mass of } CO_2}{	ext{Mass of compound}} 	imes 100$$\% 	ext{ of } C = \frac{12}{44} 	imes \frac{0.22}{0.24} 	imes 100 = 25 \%$Step $2$: Given percentage of Hydrogen $(H)$ = $1.66 \%$.Step $3$: Calculate the percentage of Oxygen $(O)$:$\% 	ext{ of } O = 100 - (\% 	ext{ of } C + \% 	ext{ of } H)$$\% 	ext{ of } O = 100 - (25 + 1.66) = 100 - 26.66 = 73.34 \%$.Since $73.34 \%$ is not explicitly listed in the options,the closest logical calculation based on the provided data is $25 \%$ Carbon and $73.34 \%$ Oxygen. Given the options,there might be a typo in the question's provided options,but $25 \%$ is the correct value for Carbon.

$0.24 \ g$ of an organic compound gave $0.22 \ g$ $CO_2$ on complete combustion. If it contains $1.66 \%$ hydrogen,then the percentage of $C$ and $O$ will be

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