A and B together can complete a work in 3 day | vedclass

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(B) Let the total work be $1$ unit.Combined efficiency of $A$ and $B$ is $\frac{1}{3}$ work per day.In $2$ days,$A$ and $B$ together complete $2 	ime

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) Let the total work be $1$ unit.Combined efficiency of $A$ and $B$ is $\frac{1}{3}$ work per day.In $2$ days,$A$ and $B$ together complete $2 	imes \frac{1}{3} = \frac{2}{3}$ of the work.Remaining work $= 1 - \frac{2}{3} = \frac{1}{3}$.This remaining $\frac{1}{3}$ work is completed by $A$ in $2$ more days.Therefore,$A$'s efficiency $= \frac{1/3}{2} = \frac{1}{6}$ work per day.Since $(A + B)$'s efficiency is $\frac{1}{3}$ and $A$'s efficiency is $\frac{1}{6}$,$B$'s efficiency $= \frac{1}{3} - \frac{1}{6} = \frac{1}{6}$ work per day.Thus,$B$ alone can complete the work in $\frac{1}{1/6} = 6$ days.

$A$ and $B$ together can complete a work in $3$ days. They start together,but after $2$ days,$B$ left the work. If the work is completed after two more days,in how many days would $B$ alone do the work?

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