(C) The work rates of $A, B$ and $C$ are $\frac{1}{6}, \frac{1}{12}$ and $\frac{1}{15}$ units per day respectively.After $\frac{1}{8}$ of the work is

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(C) The work rates of $A, B$ and $C$ are $\frac{1}{6}, \frac{1}{12}$ and $\frac{1}{15}$ units per day respectively.After $\frac{1}{8}$ of the work is completed,the remaining work is $1 - \frac{1}{8} = \frac{7}{8}$ units.The combined work rate of $A$ and $B$ is $\frac{1}{6} + \frac{1}{12} = \frac{2+1}{12} = \frac{3}{12} = \frac{1}{4}$ units per day.Time taken by $A$ and $B$ to complete the remaining work $= \frac{\text{Remaining Work}}{\text{Combined Rate of } A+B} = \frac{7/8}{1/4} = \frac{7}{8} \times 4 = \frac{7}{2} = 3 \frac{1}{2}$ days.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Easy

$A, B$ and $C$ do a job in $6$ days,$12$ days and $15$ days respectively. After $\frac{1}{8}$ of the work is completed,$C$ leaves the job. The rest of the work is done by $A$ and $B$ together. What is the time taken to finish the remaining work? (in days)

A
$5 \frac{5}{6}$
B
$5 \frac{1}{4}$
C
$3 \frac{1}{2}$
D
$3 \frac{3}{4}$

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Time and Work and Wages

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Time and Work

$A$ can finish a work in $24$ days,$B$ in $9$ days and $C$ in $12$ days. $B$ and $C$ start the work but are forced to leave after $3$ days. The remaining work was done by $A$ in (in days):

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$A$ and $B$ can do a piece of work in $45$ days and $40$ days respectively. They began to do the work together,but $A$ leaves after some days and then $B$ completed the remaining work in $23$ days. The number of days after which $A$ left the work was:

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$A$ certain job was assigned to a group of men to do in $20$ days. But,$12$ men did not turn up for the job and the remaining men did the job in $32$ days. The original number of men in the group was:

Medium

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$A$ and $B$ can complete a piece of work in $45$ and $40$ days respectively. Both started to work together,but after some days $A$ left and $B$ alone completed the remaining work in $23$ days. For how many days did $A$ work?

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$A$ alone would take $27 \, \text{days}$ more to complete the job than if both $A$ and $B$ worked together. If $B$ worked alone, he would take $3 \, \text{days}$ more to complete the job than $A$ and $B$ working together. What time would they take if both $A$ and $B$ worked together? (in $\text{days}$)

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$A, B$ and $C$ do a job in $6$ days,$12$ days and $15$ days respectively. After $\frac{1}{8}$ of the work is completed,$C$ leaves the job. The rest of the work is done by $A$ and $B$ together. What is the time taken to finish the remaining work? (in days)

Similar Questions

$A$ can finish a work in $24$ days,$B$ in $9$ days and $C$ in $12$ days. $B$ and $C$ start the work but are forced to leave after $3$ days. The remaining work was done by $A$ in (in days):

$A$ and $B$ can do a piece of work in $45$ days and $40$ days respectively. They began to do the work together,but $A$ leaves after some days and then $B$ completed the remaining work in $23$ days. The number of days after which $A$ left the work was:

$A$ certain job was assigned to a group of men to do in $20$ days. But,$12$ men did not turn up for the job and the remaining men did the job in $32$ days. The original number of men in the group was:

$A$ and $B$ can complete a piece of work in $45$ and $40$ days respectively. Both started to work together,but after some days $A$ left and $B$ alone completed the remaining work in $23$ days. For how many days did $A$ work?

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