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Question

(C) Let the work done by the $first$,$second$,$third$,and $fourth$ person in $1$ day be $W_1, W_2, W_3$,and $W_4$ respectively.$W_1 = 1/8$,$W_2 = 1/12

Vedclass · Accepted Answer

$225$

Vedclass · Answer

(C) Let the work done by the $first$,$second$,$third$,and $fourth$ person in $1$ day be $W_1, W_2, W_3$,and $W_4$ respectively.$W_1 = 1/8$,$W_2 = 1/12$,$W_3 = 1/16$.Let the $fourth$ person complete the work in $x$ days,so $W_4 = 1/x$.Since they complete the work together in $3$ days:$3(1/8 + 1/12 + 1/16 + 1/x) = 1$$1/8 + 1/12 + 1/16 + 1/x = 1/3$$1/x = 1/3 - (6+4+3)/48 = 1/3 - 13/48 = (16-13)/48 = 3/48 = 1/16$.Thus,the $fourth$ person's work share in $3$ days is $3 	imes (1/16) = 3/16$.The wages are distributed in proportion to the work done by each person.$Fourth$ person's share $= (3/16) 	imes 1200 = 3 	imes 75 = 225$ $Rs.$

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