(sqrt{2209}-12) times 5 = ? | vedclass

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Question

(A) First,find the square root of $2209$.Since $40^2 = 1600$ and $50^2 = 2500$,the number ends in $9$,so the square root must end in $3$ or $7$. Check

Vedclass · Accepted Answer

$175$

Vedclass · Answer

(A) First,find the square root of $2209$.Since $40^2 = 1600$ and $50^2 = 2500$,the number ends in $9$,so the square root must end in $3$ or $7$. Checking $47^2 = 2209$.Now,substitute the value into the expression:$(\sqrt{2209} - 12) 	imes 5 = (47 - 12) 	imes 5$$= 35 	imes 5$$= 175$

$(\sqrt{2209}-12) \times 5 = ?$

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