$\frac{28 \times 36}{18 \% \text{ of } 50} = ?$

The ten's digit of a two-digit number is greater than the unit's digit by $7$. If we subtract $63$ from the number,the new number obtained is formed by interchanging the digits. Find the number.

$A$ number exceeds $20 \%$ of itself by $40$. The number is:

The sum of three numbers is $2$. The $1^{\text{st}}$ number is $\frac{1}{2}$ times the $2^{\text{nd}}$ number and the $3^{\text{rd}}$ number is $\frac{1}{4}$ times the $2^{\text{nd}}$ number. The $2^{\text{nd}}$ number is

If $738 A 6 A$ is divisible by $11,$ then the value of $A$ is

$69.69 - 51.54 + 73.64 = ? + 32.42$