$A$ number exceeds $20 \%$ of itself by $40$. The number is:

$\frac{1}{4}$ of a number subtracted from $\frac{1}{3}$ of the same number gives $12$. The number is:

$2438.79 - 1233.99 + 399.99 = ? + 989.99$

The sum of squares of two numbers is $68$ and the square of their difference is $36$. The product of the two numbers is

The ten's digit of a two-digit number is greater than the unit's digit by $7$. If we subtract $63$ from the number,the new number obtained is formed by interchanging the digits. Find the number.

If $34N$ is a two-digit number divisible by $11$,then what is the value of $N$?