The expression frac{8.25 times 8.25 + 6.75 ti | vedclass

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Question

(A) Let $a = 8.25$ and $b = 6.75$.The given expression is of the form $\frac{a^2 + b^2 - 2ab}{a^2 - b^2}$.Using algebraic identities,we know that $a^2

Vedclass · Accepted Answer

$0.1$

Vedclass · Answer

(A) Let $a = 8.25$ and $b = 6.75$.The given expression is of the form $\frac{a^2 + b^2 - 2ab}{a^2 - b^2}$.Using algebraic identities,we know that $a^2 + b^2 - 2ab = (a - b)^2$ and $a^2 - b^2 = (a + b)(a - b)$.Substituting these into the expression,we get: $\frac{(a - b)^2}{(a + b)(a - b)} = \frac{a - b}{a + b}$.Now,substitute the values of $a$ and $b$: $\frac{8.25 - 6.75}{8.25 + 6.75} = \frac{1.5}{15.0} = 0.1$.

The expression $\frac{8.25 \times 8.25 + 6.75 \times 6.75 - 2 \times 8.25 \times 6.75}{8.25 \times 8.25 - 6.75 \times 6.75}$ when simplified equals:

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