$24$ is divided into two parts such that $7$ times the first part added to $5$ times the second part makes $146$. The first part is

When a certain number is multiplied by $7$,the product consists entirely of fives; find the least value of such a number.

In a two-digit number, if it is known that its unit's digit exceeds its ten's digit by $2$, and that the product of the given number and the sum of its digits is equal to $144$, then the number is

$\sqrt{52 \times 27 \div 6 + 26 - 4} = ?$

In a division sum,the divisor $d$ is $10$ times the quotient $q$ and $5$ times the remainder $r$. If $r = 46$,the dividend will be:

$A$ number,when divided by $729$,leaves a remainder of $56$. What will be the remainder if the same number is divided by $27$?