In a division sum,the divisor d is 10 times t | vedclass

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(C) Given that the remainder $r = 46$.The divisor $d$ is $5$ times the remainder $r$,so $d = 5 	imes 46 = 230$.The divisor $d$ is also $10$ times the

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$5336$

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(C) Given that the remainder $r = 46$.The divisor $d$ is $5$ times the remainder $r$,so $d = 5 	imes 46 = 230$.The divisor $d$ is also $10$ times the quotient $q$,so $10q = 230$,which implies $q = 23$.Using the division algorithm: $	ext{Dividend} = (	ext{Divisor} 	imes 	ext{Quotient}) + 	ext{Remainder}$.Substituting the values: $	ext{Dividend} = (230 	imes 23) + 46$.Calculating the product: $230 	imes 23 = 5290$.Adding the remainder: $5290 + 46 = 5336$.Therefore,the dividend is $5336$.

In a division sum,the divisor $d$ is $10$ times the quotient $q$ and $5$ times the remainder $r$. If $r = 46$,the dividend will be:

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