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(C) Let the two natural numbers be $x$ and $y$.Given $xy = 17$.Since $17$ is a prime number,the only natural numbers whose product is $17$ are $1$ and

Vedclass · Accepted Answer

$\frac{290}{289}$

Vedclass · Answer

(C) Let the two natural numbers be $x$ and $y$.Given $xy = 17$.Since $17$ is a prime number,the only natural numbers whose product is $17$ are $1$ and $17$.Thus,$x = 1$ and $y = 17$.We need to find the sum of the reciprocals of their squares,which is $\frac{1}{x^2} + \frac{1}{y^2}$.Substituting the values,we get $\frac{1}{1^2} + \frac{1}{17^2} = 1 + \frac{1}{289}$.Calculating the sum: $1 + \frac{1}{289} = \frac{289 + 1}{289} = \frac{290}{289}$.

The product of two natural numbers is $17$. Then the sum of the reciprocals of their squares is

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