frac{1}{left(2 frac{1}{3}right)}+frac{1}{left | vedclass

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(D) First,convert the mixed fractions into improper fractions:$2 \frac{1}{3} = \frac{2 	imes 3 + 1}{3} = \frac{7}{3}$$1 \frac{3}{4} = \frac{1 	imes

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(D) First,convert the mixed fractions into improper fractions:$2 \frac{1}{3} = \frac{2 	imes 3 + 1}{3} = \frac{7}{3}$$1 \frac{3}{4} = \frac{1 	imes 4 + 3}{4} = \frac{7}{4}$Now,substitute these into the expression:$\frac{1}{\left(\frac{7}{3}ight)} + \frac{1}{\left(\frac{7}{4}ight)} = \frac{3}{7} + \frac{4}{7}$Since the denominators are the same,add the numerators:$\frac{3+4}{7} = \frac{7}{7} = 1$

$\frac{1}{\left(2 \frac{1}{3}\right)}+\frac{1}{\left(1 \frac{3}{4}\right)}$ is equal to

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