3 frac{3}{4} + 4 frac{2}{5} - 3 frac{1}{8} = | vedclass

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Question

(B) First,convert the mixed fractions into improper fractions:$3 \frac{3}{4} = \frac{15}{4}$,$4 \frac{2}{5} = \frac{22}{5}$,and $3 \frac{1}{8} = \frac

Vedclass · Accepted Answer

$5 \frac{1}{40}$

Vedclass · Answer

(B) First,convert the mixed fractions into improper fractions:$3 \frac{3}{4} = \frac{15}{4}$,$4 \frac{2}{5} = \frac{22}{5}$,and $3 \frac{1}{8} = \frac{25}{8}$.Now,the expression becomes: $\frac{15}{4} + \frac{22}{5} - \frac{25}{8}$.The least common multiple $(LCM)$ of the denominators $4, 5, 	ext{ and } 8$ is $40$.Convert each fraction to have a denominator of $40$:$\frac{15 	imes 10}{4 	imes 10} = \frac{150}{40}$,$\frac{22 	imes 8}{5 	imes 8} = \frac{176}{40}$,and $\frac{25 	imes 5}{8 	imes 5} = \frac{125}{40}$.Now,perform the addition and subtraction:$\frac{150 + 176 - 125}{40} = \frac{326 - 125}{40} = \frac{201}{40}$.Finally,convert $\frac{201}{40}$ back into a mixed fraction:$201 \div 40 = 5$ with a remainder of $1$,so $\frac{201}{40} = 5 \frac{1}{40}$.

$3 \frac{3}{4} + 4 \frac{2}{5} - 3 \frac{1}{8} = ?$

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