n-propyl bromide on treatment with ethanolic | vedclass

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(B) The reaction of $n$-propyl bromide $(CH_3-CH_2-CH_2-Br)$ with ethanolic potassium hydroxide $(KOH)$ is a dehydrohalogenation reaction.This is an e

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Propene

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(B) The reaction of $n$-propyl bromide $(CH_3-CH_2-CH_2-Br)$ with ethanolic potassium hydroxide $(KOH)$ is a dehydrohalogenation reaction.This is an elimination reaction ($E2$ mechanism) where the base removes a proton from the $\beta$-carbon and the bromide ion is eliminated.$CH_3-CH_2-CH_2-Br + KOH \xrightarrow{C_2H_5OH} CH_3-CH=CH_2 + KBr + H_2O$.The product formed is $Propene$.

$n$-propyl bromide on treatment with ethanolic potassium hydroxide produces

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