4 coins are tossed once. Find the probability | vedclass

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(A) When $4$ coins are tossed,the total number of possible outcomes is $2^n$,where $n$ is the number of coins.Here,$n = 4$,so the total outcomes = $2^

Vedclass · Accepted Answer

$\frac{1}{16}$

Vedclass · Answer

(A) When $4$ coins are tossed,the total number of possible outcomes is $2^n$,where $n$ is the number of coins.Here,$n = 4$,so the total outcomes = $2^4 = 16$.The sample space $S$ consists of all possible combinations of Heads $(H)$ and Tails $(T)$:$S = \{HHHH, HHHT, HHTH, HTHH, THHH, HHTT, HTHT, HTTH, THTH, THHT, TTHH, TTHT, TTTH, THTT, HTTT, TTTT\}$.There is only $1$ favorable outcome for getting $4$ tails,which is ${TTTT}$.Therefore,the probability of getting $4$ tails is given by:$P(4 	ext{ tails}) = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{1}{16}$.

$4$ coins are tossed once. Find the probability of $4$ tails.

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