When two dice are thrown simultaneously,what | vedclass

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(B) When two dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.The favorable outcomes where the numbers on both dice a

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$1/6$

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(B) When two dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.The favorable outcomes where the numbers on both dice are equal are $(1, 1), (2, 2), (3, 3), (4, 4), (5, 5),$ and $(6, 6)$.Therefore,the number of favorable outcomes is $n(E) = 6$.The probability of an event is given by $P(E) = \frac{n(E)}{n(S)}$.Substituting the values,we get $P(E) = \frac{6}{36} = \frac{1}{6}$.

When two dice are thrown simultaneously,what is the probability that the numbers appeared on both dice are equal?

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