A coin is tossed twice. The probability of ge | vedclass

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(B) When a coin is tossed twice,the sample space $S$ is given by: $S = \{(H, H), (H, T), (T, H), (T, T)\}$.The total number of possible outcomes is $n

Vedclass · Accepted Answer

$\frac{1}{4}$

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(B) When a coin is tossed twice,the sample space $S$ is given by: $S = \{(H, H), (H, T), (T, H), (T, T)\}$.The total number of possible outcomes is $n(S) = 4$.Let $E$ be the event of getting a head both times. The favorable outcome is $E = \{(H, H)\}$.The number of favorable outcomes is $n(E) = 1$.The probability $P(E)$ is given by the formula: $P(E) = \frac{n(E)}{n(S)} = \frac{1}{4}$.

$A$ coin is tossed twice. The probability of getting head both the times is

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