4 coins are tossed once. Find the probability | vedclass

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(C) When $4$ coins are tossed,the total number of possible outcomes is $2^4 = 16$.The number of ways to get exactly $2$ tails out of $4$ coins is give

Vedclass · Accepted Answer

$\frac{3}{8}$

Vedclass · Answer

(C) When $4$ coins are tossed,the total number of possible outcomes is $2^4 = 16$.The number of ways to get exactly $2$ tails out of $4$ coins is given by the combination formula $^nC_r$,where $n=4$ and $r=2$.$^4C_2 = \frac{4!}{2!(4-2)!} = \frac{4 	imes 3}{2 	imes 1} = 6$.The favourable outcomes are: $HHTT, HTHT, HTTH, THHT, THTH, TTHH$.Therefore,the probability of getting exactly $2$ tails is $P = \frac{	ext{Favourable outcomes}}{	ext{Total outcomes}} = \frac{6}{16} = \frac{3}{8}$.

$4$ coins are tossed once. Find the probability of getting exactly $2$ tails.

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