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(B) When $2$ dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $A$ be the event of getting a product that is a per

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$\frac{2}{9}$

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(B) When $2$ dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $A$ be the event of getting a product that is a perfect square.The pairs $(x, y)$ such that $x 	imes y$ is a perfect square are:$(1, 1) ightarrow 1 	imes 1 = 1 = 1^2$$(1, 4) ightarrow 1 	imes 4 = 4 = 2^2$$(2, 2) ightarrow 2 	imes 2 = 4 = 2^2$$(3, 3) ightarrow 3 	imes 3 = 9 = 3^2$$(4, 1) ightarrow 4 	imes 1 = 4 = 2^2$$(4, 4) ightarrow 4 	imes 4 = 16 = 4^2$$(5, 5) ightarrow 5 	imes 5 = 25 = 5^2$$(6, 6) ightarrow 6 	imes 6 = 36 = 6^2$Thus,the set of favorable outcomes is $A = \{(1, 1), (1, 4), (2, 2), (3, 3), (4, 1), (4, 4), (5, 5), (6, 6)\}$.The number of favorable outcomes is $n(A) = 8$.The probability $P(A) = \frac{n(A)}{n(S)} = \frac{8}{36} = \frac{2}{9}$.

$2$ dice are thrown. Find the probability of getting the product as a perfect square (square of a natural number).

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