I. x^{2}+10 x+24=0II. 4 y^{2}-17 y+18=0 | vedclass

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(D) For equation $I: x^{2}+10 x+24=0$Factorizing the quadratic equation: $x^{2}+6 x+4 x+24=0$$x(x+6)+4(x+6)=0$$(x+4)(x+6)=0$Thus,$x = -4$ or $x = -6$.

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$x < y$

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(D) For equation $I: x^{2}+10 x+24=0$Factorizing the quadratic equation: $x^{2}+6 x+4 x+24=0$$x(x+6)+4(x+6)=0$$(x+4)(x+6)=0$Thus,$x = -4$ or $x = -6$.For equation $II: 4 y^{2}-17 y+18=0$Factorizing the quadratic equation: $4 y^{2}-8 y-9 y+18=0$$4 y(y-2)-9(y-2)=0$$(4 y-9)(y-2)=0$Thus,$y = \frac{9}{4} = 2.25$ or $y = 2$.Comparing the values:$x$ values are $\{-4, -6\}$ and $y$ values are $\{2.25, 2\}$.Since both values of $x$ are negative and both values of $y$ are positive,it is clear that $x < y$.

$I. x^{2}+10 x+24=0$
$II. 4 y^{2}-17 y+18=0$

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$I. x^{2}+10 x+24=0$$II. 4 y^{2}-17 y+18=0$