What is the pitch of one turn of the DNA heli | vedclass

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Question

(A) In the $B-DNA$ structure,the distance between two consecutive base pairs is $0.34 \, nm$ $(3.4 \, \mathring{A})$.One full turn of the $DNA$ helix

Vedclass · Accepted Answer

$3.4 \, nm$

Vedclass · Answer

(A) In the $B-DNA$ structure,the distance between two consecutive base pairs is $0.34 \, nm$ $(3.4 \, \mathring{A})$.One full turn of the $DNA$ helix contains $10$ base pairs.Therefore,the pitch of one turn is calculated as $10 	imes 0.34 \, nm = 3.4 \, nm$ (or $34 \, \mathring{A}$).Since $3.4 \, nm$ is equivalent to $34 \, \mathring{A}$,and the options provided list $3.4 \, nm$ as the correct value for the pitch,option $A$ is the correct answer.

Column-$I$	Column-$II$
$(a)$ $\phi \times 174$ bacteriophage	$(i)$ $48502 \ \text{b.p}$
$(b)$ Human (diploid)	$(ii)$ $5386$ bases
$(c)$ $E. coli$	$(iii)$ $6.6 \times 10^9 \ \text{b.p}$
$(d)$ $\lambda$-phage	$(iv)$ $4.6 \times 10^6 \ \text{b.p}$

What is the pitch of one turn of the $DNA$ helix?

Similar Questions

Which scientists proposed the complete and systematic model of $DNA$?

$A$ nucleosome has a histone octamer made up of:

$NHC$ protein stands for.......

Match the following columns $:-$

Column-$I$ Column-$II$

$(a)$ $\phi \times 174$ bacteriophage $(i)$ $48502 \ \text{b.p}$

$(b)$ Human (diploid) $(ii)$ $5386$ bases

$(c)$ $E. coli$ $(iii)$ $6.6 \times 10^9 \ \text{b.p}$

$(d)$ $\lambda$-phage $(iv)$ $4.6 \times 10^6 \ \text{b.p}$

$DNA$ differs from $RNA$ in:

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