P(x_{1}, y_{1}) and Q(x_{2}, y_{2}) are the g | vedclass

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(C) If a line segment $\overline{PQ}$ is parallel to the $Y$-axis,the $x$-coordinates of all points on the line segment must be equal. Therefore,$x_{1

Vedclass · Accepted Answer

$|y_{1}-y_{2}|$

Vedclass · Answer

(C) If a line segment $\overline{PQ}$ is parallel to the $Y$-axis,the $x$-coordinates of all points on the line segment must be equal. Therefore,$x_{1} = x_{2}$. The distance formula between two points $P(x_{1}, y_{1})$ and $Q(x_{2}, y_{2})$ is given by $d = \sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}$. Substituting $x_{1} = x_{2}$ into the formula: $PQ = \sqrt{(x_{1}-x_{1})^2 + (y_{2}-y_{1})^2}$ $PQ = \sqrt{0^2 + (y_{2}-y_{1})^2}$ $PQ = \sqrt{(y_{2}-y_{1})^2} = |y_{2}-y_{1}| = |y_{1}-y_{2}|$. Thus,the distance is $|y_{1}-y_{2}|$.

$P(x_{1}, y_{1})$ and $Q(x_{2}, y_{2})$ are the given points. If $\overline{PQ}$ is parallel to the $Y$-axis,then $PQ = \dots$

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