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(D) Given that $\Delta ABC \sim \Delta XYZ$ for the correspondence $ABC \leftrightarrow XYZ$.According to the theorem of areas of similar triangles,th

Vedclass · Accepted Answer

$200$

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(D) Given that $\Delta ABC \sim \Delta XYZ$ for the correspondence $ABC \leftrightarrow XYZ$.According to the theorem of areas of similar triangles,the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.Therefore,$\frac{	ext{Area}(\Delta ABC)}{	ext{Area}(\Delta XYZ)} = \left(\frac{BC}{YZ}ight)^2$.Substituting the given values: $\frac{72}{	ext{Area}(\Delta XYZ)} = \left(\frac{6}{10}ight)^2$.$\frac{72}{	ext{Area}(\Delta XYZ)} = \frac{36}{100}$.$	ext{Area}(\Delta XYZ) = \frac{72 	imes 100}{36}$.$	ext{Area}(\Delta XYZ) = 2 	imes 100 = 200$.

If $\Delta ABC \sim \Delta XYZ$ for the correspondence $ABC \leftrightarrow XYZ$. If $\text{Area}(\Delta ABC) = 72$,$BC = 6$,and $YZ = 10$,then $\text{Area}(\Delta XYZ) = \dots$

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