angle PQR and angle PQS are a linear pair of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Since $\angle PQR$ and $\angle PQS$ form a linear pair,their sum is $180^{\circ}$.$\angle PQR + \angle PQS = 180^{\circ}$ (Equation $1$).Given tha

Vedclass · Accepted Answer

$81^{\circ}$ and $99^{\circ}$

Vedclass · Answer

(C) Since $\angle PQR$ and $\angle PQS$ form a linear pair,their sum is $180^{\circ}$.$\angle PQR + \angle PQS = 180^{\circ}$ (Equation $1$).Given that $11 \angle PQR = 9 \angle PQS$,we can write $\angle PQS = \frac{11}{9} \angle PQR$.Substitute this into Equation $1$:$\angle PQR + \frac{11}{9} \angle PQR = 180^{\circ}$.$\frac{9 \angle PQR + 11 \angle PQR}{9} = 180^{\circ}$.$\frac{20 \angle PQR}{9} = 180^{\circ}$.$20 \angle PQR = 1620^{\circ}$.$\angle PQR = \frac{1620^{\circ}}{20} = 81^{\circ}$.Now,find $\angle PQS$:$\angle PQS = 180^{\circ} - 81^{\circ} = 99^{\circ}$.Thus,$\angle PQR = 81^{\circ}$ and $\angle PQS = 99^{\circ}$.

$\angle PQR$ and $\angle PQS$ are a linear pair of angles. If $11 \angle PQR = 9 \angle PQS$,then find $\angle PQR$ and $\angle PQS$.

Similar Questions

$\angle P$ and $\angle Q$ are complementary angles. If $\angle P = 3x + 15^{\circ}$ and $\angle Q = x + 7^{\circ}$,then find $\angle P$ and $\angle Q$.

If two parallel lines are intersected by a transversal,then interior angles on the same side of the transversal are $\ldots \ldots . . .$

In the following figure,$\angle DBC = 70^{\circ}$ and ray $BP$ is the bisector of $\angle DBA$. Find $\angle PBC$ and reflex $\angle PBD$.

$\angle PRT$ is an exterior angle of $\Delta PQR$. If $\angle P = 70^{\circ}$ and $\angle Q = 50^{\circ}$,then $\angle PRT = \ldots$ (in $^{\circ}$)

In the figure,$AB$,$CD$,and $EF$ are three lines concurrent at $O$. Find the value of $y$. (in $^{\circ}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module