Delta ABC sim Delta PQR for the correspondenc | vedclass

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Question

(B) Given that $\Delta ABC \sim \Delta PQR$ under the correspondence $ABC \leftrightarrow QPR.$This implies that $\angle A = \angle Q,$ $\angle B = \a

Vedclass · Accepted Answer

$3 : 2 : 4$

Vedclass · Answer

(B) Given that $\Delta ABC \sim \Delta PQR$ under the correspondence $ABC \leftrightarrow QPR.$This implies that $\angle A = \angle Q,$ $\angle B = \angle P,$ and $\angle C = \angle R.$We are given the ratio $m \angle P : m \angle Q : m \angle R = 2 : 3 : 4.$Substituting the corresponding angles:$m \angle B : m \angle A : m \angle C = 2 : 3 : 4.$Rearranging the order to $m \angle A : m \angle B : m \angle C,$ we get $3 : 2 : 4.$Therefore,the correct ratio is $3 : 2 : 4.$

$\Delta ABC \sim \Delta PQR$ for the correspondence $ABC \leftrightarrow QPR.$ If $m \angle P : m \angle Q : m \angle R = 2 : 3 : 4,$ then $m \angle A : m \angle B : m \angle C = \ldots$

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