$\cot \theta \cdot \tan \theta = \dots$
- A$\cot^{2} \theta + \tan^{2} \theta$
- B$0$
- C$\sin \theta \cdot \cos \theta$
- D$1$
Explore More
Similar Questions
Prove that,$\tan \theta + \tan (90^{\circ} - \theta) = \sec \theta \sec (90^{\circ} - \theta)$
Medium
View SolutionIf $\cos \theta = \frac{15}{17}$,then the value of $\operatorname{cosec} \theta + \cot \theta$ is .........
Easy
View SolutionWrite 'True' or 'False' and justify your answer.
The value of the expression $(\cos^{2} 23^{\circ} - \sin^{2} 67^{\circ})$ is positive.
The value of the expression $(\cos^{2} 23^{\circ} - \sin^{2} 67^{\circ})$ is positive.
Medium
View SolutionIn $\Delta ABC$,$m \angle B = 90^{\circ}$,$BC = 3$ and $AC = 5$,then $\tan A = \ldots$
Easy
View SolutionIf $\tan ^{2} \theta = \sin ^{2} \theta + \cos ^{2} \theta$,then $\theta = \ldots$ (in $^{\circ}$)
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo