Identify the product of the following reactio | vedclass

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(B) The reaction proceeds as follows:$1$. The Grignard reagent $CH_3MgBr$ performs a $1,4$-conjugate addition (Michael addition) to the $\alpha,\beta$

Vedclass · Accepted Answer

$Ph-CH(CH_3)-CH_2-CH_2-NH_2$

Vedclass · Answer

(B) The reaction proceeds as follows:$1$. The Grignard reagent $CH_3MgBr$ performs a $1,4$-conjugate addition (Michael addition) to the $\alpha,\beta$-unsaturated nitrile $Ph-CH=CH-CN$. The $CH_3$ group attacks the $\beta$-carbon,and the double bond shifts to the $C=N$ bond,forming an imine intermediate: $Ph-CH(CH_3)-CH_2-C=N$.$2$. Upon hydrolysis with $H_3O^+$,the imine is typically converted to an aldehyde or ketone,but in the presence of $NaBH_4$,the imine group $(-C=N)$ is reduced to an amine $(-CH_2-NH_2)$.$3$. The final product is $Ph-CH(CH_3)-CH_2-CH_2-NH_2$.

Identify the product of the following reaction:
$Ph-CH=CH-CN$ $\xrightarrow[2. H_3O^+]{1. CH_3MgBr}$ $\xrightarrow{NaBH_4, \Delta} \text{Product}$

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Identify the product of the following reaction:$Ph-CH=CH-CN$ $\xrightarrow[2. H_3O^+]{1. CH_3MgBr}$ $\xrightarrow{NaBH_4, \Delta} \text{Product}$