A uniform rod of mass M and length L is place | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The acceleration of the centre of mass of a system depends only on the net external force acting on the system,regardless of the point of applicat

Vedclass · Accepted Answer

$F/M$

Vedclass · Answer

(A) The acceleration of the centre of mass of a system depends only on the net external force acting on the system,regardless of the point of application of the force.According to Newton's second law,the acceleration $a_{cm}$ of the centre of mass is given by $a_{cm} = \frac{F_{net}}{M}$.Here,the net external force acting on the rod is the applied force $F$.Therefore,the acceleration of the centre of mass is $a_{cm} = \frac{F}{M}$.This acceleration is independent of the angle $	heta$ at which the force is applied,as the entire force $F$ contributes to the translational motion of the centre of mass.

$A$ uniform rod of mass $M$ and length $L$ is placed on a smooth horizontal surface. $A$ horizontal force $F$ is applied at one end of the rod at an angle $\theta$ with the rod. The acceleration of the centre of mass of the rod is:

Similar Questions

In the given figure,if the speed given to block $A$ is $10\,m/s$ and block $B$ is initially at rest,then the speed of the centre of mass after $10\,s$ will be ....... $m/s$.

Two bodies of masses $m_1$ and $m_2$ are connected by a massless string passing over a massless,frictionless pulley as shown in the figure. Given $m_2 < m_1$. The acceleration of the center of mass of the system is:

Two balls are thrown in the air. The second ball is thrown $2 \ s$ after the first ball. What is the acceleration of the center of mass of the two balls while they are in the air?

Show that the total momentum of a system of particles is equal to the product of the total mass of the system and the velocity of the centre of mass.

Two particles of mass $m_1$ and $m_2$ are separated by a distance $d$. If the first particle is moved towards the centre of mass by a distance $x$,then the distance by which the second particle must be moved towards the centre of mass to keep the centre of mass at the same position is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module