CO_{2} diffuses into ...A... and forms HCO_{3 | vedclass

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(B) The transport of $CO_{2}$ occurs primarily in the form of bicarbonate ions $(HCO_{3}^{-})$.$1$. At the tissue level, $CO_{2}$ produced by metaboli

Vedclass · Accepted Answer

$A-$ $RBC$, $B-$ alveolar, $C-$ bicarbonate, $D-$ $CO_{2}$

Vedclass · Answer

(B) The transport of $CO_{2}$ occurs primarily in the form of bicarbonate ions $(HCO_{3}^{-})$.$1$. At the tissue level, $CO_{2}$ produced by metabolic activities diffuses into the blood and enters the Red Blood Cells $(RBCs)$ $(A = RBC)$.$2$. Inside the $RBCs$, $CO_{2}$ reacts with water in the presence of the enzyme carbonic anhydrase to form $HCO_{3}^{-}$ and $H^{+}$ $(C = 	ext{bicarbonate})$.$3$. This blood is transported to the lungs. At the alveolar site, the partial pressure of $CO_{2}$ $(pCO_{2})$ is low $(B = 	ext{alveolar})$.$4$. Due to low $pCO_{2}$, the reaction proceeds in the opposite direction, converting $HCO_{3}^{-}$ back into $CO_{2}$, which is then released into the alveoli and exhaled $(D = CO_{2})$.Therefore, the correct sequence is $A = RBC, B = 	ext{alveolar}, C = 	ext{bicarbonate}, D = CO_{2}$.

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