C_6H_5-CH=CHCHO xrightarrow{X} C_6H_5-CH=CHCH | vedclass

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Question

(B) $NaBH_4$ is a selective reducing agent that reduces the carbonyl group $(-CHO)$ to a primary alcohol $(-CH_2OH)$ without affecting the carbon-carb

Vedclass · Accepted Answer

$NaBH_4$

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(B) $NaBH_4$ is a selective reducing agent that reduces the carbonyl group $(-CHO)$ to a primary alcohol $(-CH_2OH)$ without affecting the carbon-carbon double bond $(C=C)$.$H_2/Ni$ is a non-selective reducing agent that would reduce both the carbonyl group and the carbon-carbon double bond.Therefore,the correct reagent is $NaBH_4$.$C_6H_5-CH=CHCHO \xrightarrow{NaBH_4} C_6H_5-CH=CHCH_2OH$

$C_6H_5-CH=CHCHO \xrightarrow{X} C_6H_5-CH=CHCH_2OH$. In the above sequence,$X$ can be:

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