3 moles of a metal complex with the formula C | vedclass

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(A) The complex $Co(en)_2 Cl_3$ reacts with $AgNO_3$ to precipitate $AgCl$. Since $3$ moles of $AgCl$ are produced from $3$ moles of the complex,each

Vedclass · Accepted Answer

$6$

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(A) The complex $Co(en)_2 Cl_3$ reacts with $AgNO_3$ to precipitate $AgCl$. Since $3$ moles of $AgCl$ are produced from $3$ moles of the complex,each mole of the complex releases $1$ mole of $Cl^-$ ions.This indicates the formula is $[Co(en)_2 Cl_2]Cl$.The secondary valency corresponds to the coordination number $(C.N.)$.In $[Co(en)_2 Cl_2]Cl$,the central metal $Co$ is bonded to two bidentate $en$ ligands ($2 	imes 2 = 4$ coordination sites) and two monodentate $Cl^-$ ligands ($2 	imes 1 = 2$ coordination sites).Therefore,the coordination number $= 4 + 2 = 6$.The secondary valency of $Co$ is $6$.

Formula of the complexes	Moles of $AgCl$ precipitated per mole of complex
$(I) \ CoCl_3 \cdot 6 H_2O$	$3$
$(II) \ NiCl_3 \cdot 6 H_2O$	$2$
$(III) \ Co(SO_4)Br \cdot 5 NH_3$	$1$

$3$ moles of a metal complex with the formula $Co(en)_2 Cl_3$ gives $3$ moles of silver chloride on treatment with an excess of silver nitrate. The secondary valency of $Co$ in the complex is $.....$ (Round off to the nearest integer).

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